16g^2-94g-12=0

Solution for 16g^2-94g-12=0 equation:

16g^2-94g-12=0

a = 16; b = -94; c = -12;
Δ = b2-4ac
Δ = -942-4·16·(-12)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-98}{2*16}=\frac{-4}{32}
=-1/8
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+98}{2*16}=\frac{192}{32}
=6
$